Corporate FinanceShine plc Company

Question: Discuss about theCorporate Financefor Shine plc Company. Answer: Introduction The given assignment discusses about some of corporate finance strategies for a company that is Shine plc. The company is considering purchasing a project of new security light. For the effective decision making, strategies of corporate finance have been laid down. The assignment discusses about the cash flow analysis that is earning after taxation but before depreciation of the new security light ahs to be calculated. After this the assignment considers an analysis over net present value and internal rate of return. At last the company considers the forward contract decision making. Cash Flows of the New Security Light Earnings after taxation, but before non cash expenses are called as the cash flow from the project. In the gives case study, by deduction all the fixed and variable expenses from the regular income of the project that is annual sales, earnings after tax has been calculated. To calculate earnings after taxation but before depreciation that is cash flow, non cash expenses that is depreciation is to be deducted (Moyer, McGuigan, Rao, 2014). In calculation of cash flow of the project, depreciation is excluded. It is done because depreciation is considered as non cash expenses for the company. Depreciation does not lead to any cash flow in the financial statements of the company. Shine plc Particulars Year 1 Year 2 Year 3 Year 4 Selling units 14000 16000 16000 14000 selling price 110 120 120 100 Sales 1540000 1920000 1920000 1400000 material 420000 480000 512000 476000 Labor 210000 240000 240000 238000 Variable overhead 70000 80000 96000 98000 Interest 120000 120000 120000 120000 Depreciation 250000 250000 250000 250000 administration overhead 100000 100000 100000 100000 fixed cost 80000 80000 80000 80000 fixed overhead 500000 500000 500000 500000 consultancy 250000 0 0 0 working capital 150000 0 0 0 all cash and non cash expenses 2150000 1850000 1898000 1862000 earnings before tax -610000 70000 22000 -462000 tax 8750 2750 earnings after tax -610000 61250 19250 -462000 The cash inflow of the project has been described in the below table as earnings after tax but before depreciation. In the given case study the initial cash outlay or initial investment is -15, 00,000. Hence the net cash inflow of new security light can be calculated as -2, 60,000. year earnings after tax depreciation earnings after tax before depreciation initial outlay -1500000 -1500000 1 -610000 250000 -360000 2 61250 250000 311250 3 19250 250000 269250 4 -462000 250000 -212000 cash flow -1508500 As it has been clear from the given table that the cash flow of the new security light comes out to be negative, hence it is suggested for Shine Plc to not to accept the new security light project (Brigham, Ehrhardt, 2007). NPV (Net Present Value) In the given case study it has been given that the company follows a capital rate of 13%. The Net present value is calculated by firstly calculating present value of cash inflows (Shapiro, 2008). After present value of cash inflows, the initial investment has to be subtracted from it. If the net present value comes out to be positive, the project should be accepted. But if, the Net present value comes out to be negative, the project should be rejected (Lasher, 2016). year earnings after tax depreciation earnings after tax before depreciation PV factor @ 13% Present Value initial outlay -1500000 -1500000 -1500000 1 -610000 250000 -360000 0.885 -318600 2 61250 250000 311250 0.7831 243739.875 3 19250 250000 269250 0.6931 186617.175 4 -462000 250000 -212000 0.6133 -130019.6 cash flow -1508500 total present value -18262.55 Net Present Value -1481737.45 By analyzing over the given table, it can be observed that the net present value comes out to be positive. Hence in such case it is suggested for Shine Plc to accept the new security light project because it is giving positive net present value (Khan Jain, 2007). IRR (Internal Rate of Return) of New Product In the above stated formula, net present value at lower rate is the amount which is calculated by subtraction of multiplication of lower present value factor and the cash flows of the project, and initial investment. While present value at lower rate is the amount which can be calculated by multiplying the cash flows of the project by lower present value factor. Here present value at higher rate can be calculated by multiplying cash flows of the project with higher present value factor (Peterson Fabozzi, 2002). In the given case internal rate of return can be calculated as: year earnings after tax depreciation earnings after tax before depreciation PV factor @ 13% Present Value PV factor @ 15% present value initial outlay -1500000 -1500000 -1500000 -1500000 1 -610000 250000 -360000 0.885 -318600 0.876 -315360 2 61250 250000 311250 0.7831 243739.875 0.7561 235336.125 3 19250 250000 269250 0.6931 186617.175 0.6575 177031.875 4 -462000 250000 -212000 0.6133 -130019.6 0.5718 -121221.6 cash flow -1508500 total present value -18262.55 -24213.6 Net Present Value -1481737.45 1475786.4 present value@13%- present Value @ 15% -2957523.85 internal rate of return 14% Internal rate of return helps an organization in selection of the best project from the various alternatives. If the organization has internal rate of return less than the required rate of return then the companys cost of capital, then the project should be accepted. While if the company has greater internal rate of return than companys cost of capital, the project should be rejected. In calculation of IRR, shine plc has assumed 15% rate of return (Cristodoulou). Hence by analyzing the company internal rate of return it can be said that, shine plc has a negative internal rate if return of 14%. The major limitation with internal rate of return is that it does not consider the future cash flows. Hence by considering internal rate of return, it is recommended for shine Plc to not to accept the project. Report to Senior Management Regarding Project By analyzing the above data and calculations, it can be observed that the company has negative cash flows. However the company has positive net present value. Hence by analyzing the net present value it can be said that the project should be accepted. By comparing between shine plc internal rate of return which is, 14% and its cost of capital which is given in the case study as 13%. It can be said that the project should not to be accepted. It is due to negative internal rate of return. Hence it can be said that by investing in new security light, the company will not get profitable results (Bierman Smidth2012). Forward Exchange Requirement Forward contract is an agreement between two parties, in which there is an obligation on the part of buyer to purchase the asset and on the part of seller to sell the product at a fixed determined price. This type of contracting is usually done for long term basis to save both the firms from uncertainty. Besides this, the use of forward contract is higher in case of foreign contracts. This is done due to difference in the structure of the economy, politics, market and many more. It is usually done to save both the parties from foreign currency exchange rates and any market fluctuations (Delaney Whittington, 2007). The US firm has decided to buy the products of shine plc at $3.4 million. The payment would be made to the shine plc company in three months time. However it has been estimated by shine Plc that the cost of this forward contract to the company would be 3.05 million. By observing the whole scenario regarding forward contract, it can be said that the company would arrive at a profit of 0.15. The profit is arrived by subtracting $3.4million as converted into 3.20 million and 3.05. Hence by analyzing over the forward contracting transaction, it can be said that the company has done profitable transaction, and company should accept the offer of US firm. Besides this the company has observed that the bank will pay Euros in return of dollar to company as 3.25, while the company has demanded 3.18. Hence by this it can be analyzed that the company is at liquidity position, as it helps the company in earning profit of 0.07 Euros. Conclusion By analyzing the given assignment, it can be concluded that the new security light should be considered by the company, and it should not accepted. This is due to negative cash flows of the company. Besides this the company has negative net present value and negative internal rate of return. This shows that the company will not get any profitable return as expected by investing in the new project of new security light. While analyzing the forward contract as done between the U.S. firm and the shine plc, it can be concluded that the company has made a good decision. It is due to having a profitable amount of 0.15 million. Hence at last it can be said that the company should reject the proposal of new security line and accept the proposal of U.S. firm on the basis of forward contract. References Bierman, H Smidth, J, S,. (2012) The capital budgeting decision: Economic analysis of investment projects, edition 9th, Routledge, Abingdon Brigham, E Ehrhardt, M,. (2007) Financial management: Theory Practice, Thomson, USA Cristodoulou, A,. The internal rate of return problems and matters of solution. Retrieved on https://www.iamb.it/share/img_new_medit_articoli/802_32cristodoulou.pdf Delaney, P, R Whittington, O,R,. (2007) Wiley CPA examination review 2007-2008, problems and solutions, John Wiley sons, Canada Khan Jain,. (2007) Financial management, Tata McGraw hill, New Delhi Lasher, W, R,. (2016) Practical financial management, Cengage learning, USA Moyer, R, C,. McGuigan, J, R Rao, R, O.P. (2014) Contemporary financial management, Cengage learning, USA Peterson, P,P Fabozzi, F, J,. (2002) Capital budgeting: Theory and practice, John Wiley sons, Canada Shapiro,. (2008) Capital budgeting and Investment analysis, Pearson education India

Mathematics Portfolio Sl Essay Example

Mathematics Portfolio Sl Essay Mathematics Standard Level Teacher: Mr. Lazaro Name: Fatema Ismailjee IB 1 2011 Sequence is a set of things (usually numbers) that are in order. e. g. 1, 2, 3, 4, Where 1 is the first term, 2 is the second term and so on. ( in the end means that the sequence goes on forever. Three dots in the middle e. g. 1, 2, 3 7, 8 indicate that the pattern continues until the next number appears. There is finite and infinite sequence, infinite sequence is when the sequence has no end and finite is a set with a function e. g. {1, 3, n} Calculating specific terms leads to an nth  term formula. Before creating a rule of calculation, you need to realize that sequences are functions with the specific domain of the counting numbers {1, 2, 3, 4, 5, }. So the n replaces x  as the input variable and instead of writing  y, we use  an  as the output variable.Arithmetic sequence: the difference between one term and the next is a constant in arithmetic sequence. The general formula is an  = a1à ‚  + (n 1) d Geometric sequence: A geometric sequence is a group of numbers where each term after the first is found by multiplying the previous one by a fixed non zero number called common ratio. The general formula is an = a1 ? rn-1 Series is the sum of terms of a sequence. Sn = x1 + x2 +. xn Arithmetic series: The general formula is Sn  = n/2(a1  + an) Geometric series: a series which has a constant ratio between terms.The general formula is Sn = a1 (1 – rn) 1 r TRIANGULAR NUMBERS Triangular number is the number of dots in an equilateral triangle uniformly filled with dots. This is an investigation task whereby I will try to find number of shapes of geometric figures which form triangular numbers. I will use different sources of information to attain shapes and figures. For the calculations required, different math techniques will be used for the different shape obtained. Aim In this task I will consider geometric shapes which lead to special numbers.The simplest exa mples of these are square numbers, 1, 4, 9, 16, which can be represented by squares of side 1, 2, 3 and 4. The following diagrams show a triangular pattern of evenly spaced dots. The numbers of dots in each diagram are examples of triangular numbers (1, 3, 6, ). .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 3 6 10 15 There is a sequence of the number of dots in the triangular shape above.Complete the triangular sequence with three more terms. . . . . . . . . . . . . . . . . . . . . . 21 dots . . . . . . . . . . . . . . . . . . . . . . . . . . . . 28 dots . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 36 dots Find a general statement that represents the nth triangular number in terms of n. In words: The top row has one dot and each successive row under it has one more dot.Using the formula: 1. Find the common difference between the numbers in the sequence. 2. Use the general formula tn = an2 + bn + c. 3. Three equations will be forme d. Using the elimination method find the coefficients i. e. a, b and c. 4. Substitute in the general formula. The general statement can be reached by following the steps above. Common difference: d= U2 – U1 = U3 – U2 1, 3, 6, 10, 15, d= 3-1 = 2 6-3 = 3 10-6 = 4 15-10 = 5 d= 3-2 = 1 4-3 = 1 5-4 = 1 The difference in terms is found in the second stage so the formula will be n2 . 2 Testing: n = 1 , triangular number = 1 22 = 12 1 12 = 12 n = 2, triangular number = 3 n22 = 92 3 92 = 32 32 12 = 12 12 so this will be 12 n therefore, 2 12 n2 = 12n As the common difference in the second stage is 1, it can be deduced that the formula for the nth term is a quadratic equation. I will use the general formula to find the nth term, tn = an2 + bn + c where a and b are the coefficients and c is constant and n is the number of term. 2 n2 = 12 n = n2 + n 2 When n = 1 1 = a (1)2 + b (1) + c 1 = a + b + c . (i) n = 2 3 = a (2)2 + b (2) + c 3 = 4a + 2b + c . (ii) n = 3 6 = a (3)2 + b (3 ) + c 6 = 9a + 3b + c . (iii) Using the elimination method: 3 = 4a + 2b + c 6 = 9a + 3b + c 1 = a + b + c 3 = 4a + 2b + c 2 = 3a + b 3 = 5a + b Now that two equations are obtained: To find the variables i. e. a, b one of them is eliminated.In this case the equations are being subtracted. b will be eliminated first in order to find a. Substitute the values of a in the equation to find the value of b. 3 = 5a + b 3 = 5a + b 1 = a + b + c 2 = 3a + b 3 = 5(1 ) + b 1 = 1 + 1 +c 2 2 2 1 = 2a 3 5 = b 2 2 2 a = 1 b = 1 c = 0 2 Therefore the formula for finding the nth term will be as follows: tn = 1n2 + 1n 2 2 tn = n2 + n 2 Use of technology to find the general statement: Calculator used: CASIO fx-9750 GA PLUS n| 1| 2| 3| 4| 5| 6| 7| y| 1| 3| 6| 10| 15| 21| 28| Let n = x 1. Select STAT. 2. Encode values for x in list 1 and for y in list 2. 3. Select GRPH (by pressing F1). 4. Select GPH1 (by pressing F1 again). 5. Select x^2 (by pressing F3). The display will show: a = 1 2 b = 1 c = 0 y = ax 2 + bx + c 1n2 + 1n y = 2 2 = n2 + n 2 Consider stellar (star) shapes with p vertices, leading to p-stellar numbers. The first four representations for a star with six vertices are shown in the four stages S1 – S4 below. The 6-stellar number at each stage is the total number of dots in the diagram. Find the number of dots (i. e. the stellar number) in each stage up to S6. Stellar numbers are figurate number, based on the number of dots of units that can fit in a centred hexagon or star shapes. S1 – S4 are the numbers of dots in the stars.To find up to S6 find the common difference (d) followed by the addition of numbers of star in the previous star. S1 has 1 dot S2 has 13 dots S3 has 37 dots S4 has 73 dots Find the common difference between the terms. d = S2 – S1 S3 – S2 d = 13 – 1 = 12 37 – 13 = 24 73 – 37 = 36 As the difference is not constant, find the difference within the answers. d = 36 – 24 = 12 13 – 12 = 12 The c ommon difference is 12. S 5 = 36 + 12 = 48 73 + 48 = 121dots S6 = 48 + 12 = 60 121 + 60 = 181dots Find an expression for the 6-stellar number at stage S7. As shown above, the common difference is 12.As it’s a sequence it follows the same trend therefore: To find the next number of dots in the sequence, add it with 12 first and from the second star add it with the multiples of 12, i. e. 24, 36, 48 etc. S6 = 48 + 12 = 60 = S5 + 60 = 121 + 60 = 181 S7 = 60 + 12 = 72 = S6 + 72 = 181 + 72 = 253 S7 = 253 Find a general statement for the 6-stellar number at stage Sn in terms of n. Use the same general formula to obtain the three equations: The general formula: tn = an2 + bn + c When n = 1 1 = a (1)2 + b (1) + c 1 = a + b + c . (i) n = 2 13 = a (2)2 + b (2) + c 13 = 4a + 2b + c . (ii) = 3 37 = a (3)2 + b (3) + c 37 = 9a + 3b + c . (iii) Using the elimination method: 37 = 9a + 3b + c 13 = 4a + 2b + c 13 = 4a + 2b + c 1 = a + b + c 24 = 5a + b 12 = 3a + b After attaining two equations, either of the coefficients should be eliminated. b in this case which will lead us to find a. Substitute value of a in the equation to find b. Hence, substitute values of a and b for c. 24 = 5a + b 24 = 5a + b 1 = a + b + c 2 = 3a + b 24 = 5(6) + b 1 = 6 + (-6) + c 12= 2a 24 – 30 = b 1 – 0 = c 2 2 a = 6 b = -6 c = 1 Substitute a, b and c in the general statement. General statement: tn = 6n2 – 6n + 1 Now repeat the steps above for other values of p Considering stellar (star) shapes when p=7 and when p=8 leading to p-stellar numbers. p = 7 Find the number of dots (i. e. the stellar number) in each stage up to S6. S1 has 1 dot S2 has 15 dots S3 has 43 dots S4 has 85 dots d = 15 – 1 = 14 3 – 15 = 28 85 – 43 = 42 d = 42 – 28 = 14 28 – 14 = 14 e. g. S4 = 43 + 14 = 42 S3 + 42 43 + 42 = 85 dots S 5 = 42 +14 =56 S4 + 56 85 + 56 = 141dots S6 = 56 +14 = 70 S5 + 70 141 + 70 = 211dots Find an expression for the 6-stellar number at stage S7 . As shown above, the common difference is 14. As it’s a sequence it follows the same trend therefore: To find the next number of dots in the sequence, add it with 2 first and from the second star add it with the multiples of 2, i. e. 14, 28, 42 etc. S7 = 70 + 14 = 84 S6 + 84 211 + 84 = 2955dots S7 = 295dots Find a general statement for the 6-stellar number at stage Sn in terms of n.To find the three equations, use the general formula tn = an2 + bn + c. When n = 1 1 = a (1)2 + b (1) + c 1 = a + b + c . (i) n = 2 15 = a (2)2 + b (2) + c 15 = 4a + 2b + c . (ii) n = 3 43 = a (3)2 + b (3) + c 43 = 9a + 3b + c . (iii) Three equations are obtained, to find a, b and c, the equations need to be solved. Elimination method is one of the ways from which we can attain the coefficients and constant. Using elimination method: Firstly, we need to remain with two equations at the end so subtract equations (equation iii – ii and equation ii – i) and two will be remained. 3 = 9a + 3b + c 15 = 4a + 2b + c 15 = 4a + 2b + c 1 = a + b + c 28 = 5a + b 14 = 3a + b Now that there are two equations, find a and b. Subtract the equation to eliminate one variable. After one is found, the other can be easily found by substituting the value of variable attained in the equation. 28 = 5a + b 28 = 5a + b 1 = a + b + c 14 = 3a + b 28 = 5(7) + b 1 = 7 + (-7) + c 4= 2a 28 – 35 = b 1 – 0 = c 2 2 a = 7 b = -7 c = 1 Substitute a, b and c in the general statement. General statement: tn = 7n2 – 7n + 1 p = 8 S1 has 1 dot S2 has 17 dots S3 has 49 dots S4 has 97 dots Find the common difference: d = 17 – 1 = 16 49 – 17 = 32 97 – 49 = 48 As the difference is not constant, subtract the answers to find the common difference. d = 32 – 16 = 16 48 – 32 = 16 To find the following number in the star e. g. S4 = 32 + 16 = 48 S3 + 48 49 + 48 = 97 dots The common difference is 16.If observed carefully the number is found by adding it with mu ltiples of 16 i. e. 32, 48, 64, 80 etc. S 5 = 48 +16 = 64 S4 + 64 97 + 64 = 161dots S6 = 64 + 16 = 80 S5 + 80 161 + 80 = 241dots Find an expression for the 6-stellar number at stage S7. As shown above, the common difference is 16. As it’s a sequence it follows the same trend therefore: To find the next number of dots in the sequence, add it with 16 first and from the second star add it with the multiples of 3, i. e. 32, 48, 64 etc. S7 = 80 + 16 = 96 S6 + 96 241 + 96 = 337dots S7 = 337dots Find a general statement for the 6-stellar number at stage Sn in terms of n.I will use the same general formula to obtain the three equations: The general formula: tn = an2 + bn + c When n = 1 1 = a (1)2 + b (1) + c 1 = a + b + c . (i) n = 2 17 = a (2)2 + b (2) + c 17 = 4a + 2b + c . (ii) n = 3 49 = a (3)2 + b (3) + c 49 = 9a + 3b + c . (iii) Using the elimination method: 49 = 9a + 3b + c 17 = 4a + 2b + c 17 = 4a + 2b + c 1 = a + b + c 32 = 5a + b 16 = 3a + bNow there are two equations, so b has to eliminated by subtracting the two equations to find a. Once, a is obtained one of the equation has to be chosen and substitute the value of a in it. Hence b is obtained. 32 = 5a + b 32 = 5a + b 1 = a + b + c 16 = 3a + b 32 = 5(8) + b 1 = 3 + (-3) + c 16 = 2a 32 – 40 = b 2 2 a = 8 b = -8 c = 1 Substitute a, b and c in the general statement. General statement: tn = 8n2 – 8n + 1Hence, produce the general statement, in terms of p and n,that generates the sequence of p-stellar numbers for any value of p at stage Sn. The general statements produced are: tn = 6n2 – 6n + 1 tn = 7n2 – 7n + 1 tn = 8n2 – 8n + 1 I observed it, and reached to the conclusion that for all the three statements the number of p and number of coefficient that is a and b is the same. Therefore the general statement in terms of p and n that generates the sequence of p-stellar numbers for any value of p at stage Sn is: tn = pn2 – pn + 1 Test the validity of the general st atement. When p = 5 S1 has 1 dot S2 has 11 dots S3 has 31 dotsS4 has 61 dots Common difference: d = 11 – 1 = 10 31 – 11 = 20 61 – 31 = 30 As the difference is not constant, subtract it within the answer obtained: d = 30 – 20 = 10 20 – 10 = 10 As seen, the common difference is 5. As it’s a sequence it follows the same trend therefore: To find the next number in the sequence, add it with multiples of 5 i. e. 10, 15, 20, etc. S 5 = 30 + 10 = 40 61 + 40 = 101dots S6 = 40 + 10 = 50 = S5 + 50 = 101 + 50 = 151dots S7 = 50 + 10 = 60 = S6 + 60 = 151 + 60 = 211 S7 = 211dots The general formula: tn = an2 + bn + c When n = 1 1 = a (1)2 + b (1) + c 1 = a + b + c . (i) n = 2 1 = a (2)2 + b (2) + c 11 = 4a + 2b + c . (ii) n = 3 31 = a (3)2 + b (3) + c 31 = 9a + 3b + c . (iii) Using the elimination method: 31 = 9a + 3b + c 11 = 4a + 2b + c 11 = 4a + 2b + c 1 = a + b + c 20 = 5a + b 10 = 3a + b 20 = 5a + b 20 = 5a + b 1 = a + b + c 10 = 3a + b 20 = 5(5) + b 1 = 6 + (-6) + c 10= 2a 20 – 25 = b 1 – 0 = c 2 a = 5 b = -5 c = 1 Substitute a, b and c in the general statement. General statement: tn = 5n2 – 5n + 1 Below are the values of the formula Sn= 5n2 5n +1 n = Stage number in the 5-stellar shape. | y= total number of dots at stage ‘n’. | 1| 1| 2| 11| 3| 31| 4| 61| 5| 101| 6| 151| 7| 211| If we want to know the number of dots in the 5th term using the formula we replace n with 5 based on the formula Sn= 5n2 – 5n + 1 Sn= 5n2 – 5n + 1 Sn= 5 (5)2 – 5 (5) +1 Sn= 101 Limitation: * The value of p should be greater than or equal to 4 i. e. p ? 4. The value of p cannot be negative. It must be a positive integer. The general statement has some limitations as listed above. It is an arithmetic series as seen. It is derived from the equations generated in the 5, 6, 7-stellar shape. The coefficients in each question are equal to the corresponding stellar number p. References: Sequences.   Math Is Fun Maths Resources. Web. 12 Mar. 2011. Help for a Generic Formula for a Stellar Pattern.? Yahoo! Answers.   Yahoo! Answers Home. Web. 12 Mar. 2011. Triangular Number ENotes. com Reference.   ENotes Literature Study Guides, Lesson Plans, and More. Web. 11 Mar. 2011.

5 grammar skills you need to master for career success

5 grammar skills you need to master for career success No matter what field you’re in, it’s likely that any given job description calls for good communication skills. At the top of this list is making sure your writing and speaking skills are top-notch. Let’s look at some of the key grammar tips that make your conversation and resume are polished and professional. 1. Use possessives correctly.This is one of the most frequent grammatical errors. Always take a minute to make sure you’re using the they’re and you’re  contractions for they are and you are. Their and your are possessive pronouns. These mistakes are often some of the easiest to spot for a reader, and they are so common from people of all backgrounds and education levels. If this is an issue that makes you nervous, one way to avoid this is to avoid confusion by not using contractions. It’s totally fine to spell out you are.Rule of thumb: If you’re making a contraction, you should always have an apostrophe. Possessive pro nouns never have an apostrophe.2. Don’t speak in the third person.Sometimes we (royal we) like to be extra formal in resumes or job interviews, because we want to present ourselves as highly dignified professionals. Resist that urge. Don’t go too informal (keep it professional, always), but it is absolutely okay to say â€Å"I† or â€Å"me,† and make it personal.Rule of thumb: You’re presenting yourself. You don’t need to hide behind the third person just to be fancy.3. Don’t use jargon or tons of abbreviations.Jargon is extremely popular on resumes, because you want the reader to know that you understand the ins and outs of an industry. You talk the talk, so that must mean  you’re an insider, right? Not really. Instead, you run the risk of turning off readers if they don’t quite get the same terminology, or if that jargon is hyper-specific to, say, your current job. It’s always better to keep things generic. An d if you do use abbreviations to save space, make sure you spell it out on the first use in your resume, cover letter, email, etc.Rule of thumb: Simpler is better. You never know who’s reading.4. Don’t use unnecessary capitals.Like jargon or being overly formal, extra capitals can be a crutch when we want people to Know What We’re Talking About. You may think you’re providing emphasis that draws the reader’s eye and makes your writing easier to read, but it really just complicates things unnecessarily.Rule of thumb: Only legitimate proper nouns (names) should have capitals.5. Proofread everything three times.I can’t emphasize this enough. All of us are prone to little mistakes when we write. This is especially true when you’ve written, rewritten, and edited a resume or cover letter so many times that you stop seeing what’s in it because you know it so well. That’s inevitably where the little mistakes creep in. If at all possible, get a trusted reader to review something official before you turn it in. Having an extra pair of eyes can help you spot blatant spelling or grammar errors, and can also help ensure that you’re making sense to the reader.Rule of thumb: Do it. Then do it again.

Lo and Behold!

Lo and Behold! Lo and Behold! Lo and Behold! By Maeve Maddox A football fan posted the following: I decided to watch the Duke vs Miami game and low and behold Duke is successful this year Naturally the â€Å"low and behold† caught my eye. Was it just a typo? I hopped on my search engine to see what I could find. Apparently a lot of English speakers write low for the lo of â€Å"Lo and behold!† Some of the misspellings I found were deliberate puns in headlines above stories about something â€Å"low,† like low oil prices, low calorie recipes, and low golf scores. More, however, seemed to be the result of not knowing that the word in the expression is spelled lo and not low. Here are some examples: Low and behold! (a blog title) Low and Behold (a 2007 movie about post-Hurricane Katrina) low and behold I have some pretty awesome DOMS in the mid region (exercise site) But low and behold, some four decades later (printed rap lyrics) Low and behold it worked out great I got a laptop in the mail (testimonial on marketing site) Autumn term will all be about the Old Testament and low and behold, we’ve worked out a complete program (university site in the U.K.) Low and BeholdHow Much Work Are You Willing to do? (headline on an author’s site) If you don’t count the exotic list of words acceptable for Scrabble tournaments, English has very few two-letter words. The fact that only about twenty are in common use may account for attempts to add a little body to lo by adding another letter. Lo may derive from the imperative form of the verb to look. It has been used as an interjection at least since Beowulf was written, but the tautology â€Å"lo and behold† dates only from the 19th century. Long before that, lo–in the sense of Look! See! Behold!– was used to direct attention to something about to happen or about to be said. For, lo, the winter is past, the rain is over and gone; (Song of Solomon, 2:11, KJV.) And Lo! the Hunter of the East has caught/The Sultan’s Turret in a Noose of Light. (Rubaiyat of Omar Khayyam, Edward Fitzgerald translation.) The earliest OED citation for Lo and behold! is from a letter written in 1808. Bulwer-Lytton– he who gave us the novel opening, â€Å"It was a dark and stormy night,† used it in 1841: The fair bride was skipping down the middle..when, lo and behold! the whiskered gentleman..advanced..and cried- ‘La voil!’ (Night Morning II. iii. v. 144  ) Nowadays the expression is used both humorously and cuttingly. Tennessee Williams has Stanley use it in a tirade against Blanche: You come in here and sprinkle the place with powder and spray perfume and cover the light-bulb with a paper lantern, and lo and behold the place has turned into Egypt and you are the Queen of the Nile! (Streetcar Named Desire, scene 10). Modern novelists probably won’t find much use for the expression butâ€Å"Lo and Behold!† still has plenty of life in it for daily conversational use. People who use the expression in their blogs and online conversations may want to check the spelling. Historical novelists putting exclamations in the mouths of pre-19th century characters may want to stick to plain â€Å"Lo!† Want to improve your English in five minutes a day? Get a subscription and start receiving our writing tips and exercises daily! Keep learning! Browse the Expressions category, check our popular posts, or choose a related post below:Congratulations on or for?Rules for Capitalization in TitlesHow to Address Your Elders, Your Doctor, Young Children... and Your CEO

Finance Week 2 Essay Example | Topics and Well Written Essays - 500 words

Finance Week 2 - Essay Example I am pleased that we can use a financial calculator to help us, but if I am unsure about the variables then it won’t help me much. For interest rates, I was previously unsure about how they are determined and why they can change so quickly. After going through Chapter 6, however, I now feel like I have a good grasp of it. 2. The financial ratio that I find easiest to understand is the single future cash flow ratio because it is very straightforward and there are no added variables. By that I mean that anyone with only a basic understanding of math would be able to comprehend it because the ratio follows a pattern. The hardest financial ratios to understand are those with multiple future cash flows because the answers can be unpredictable if there is a series of unequal amounts. The cash flow timeline helps me a lot because I can visualize each cash flow in terms of where it comes from and how it influences the overall outcome. The most difficult thing is trying to figure out where the investment problems variables fit into the equation. Once I have the right equation, I can usually solve for the unknown variable because then it just becomes a simple case of math. 3. The financial calculator is both useful and challenging for me at the same time. I like it because it helps me to find the correct answer in a short amount of time. If I have figured out all the variables, then I can simply plug the numbers in and the calculator will spit out the answer. The one problem that I have with it is that I sometimes don’t fully understand why it gave me a certain answer. If I was able to work through the problem step-by-step, then I would have a better understanding of it. 4. I would describe the current level of interest rates as moderately high. Although current inflation is relatively low due to the financial crisis, there is still a lot of risk in the marketplace, and this ensures that

Report Assignment Example | Topics and Well Written Essays - 3000 words - 1

Report - Assignment Example Any children’s right forums should relate existing human rights law to the particular circumstances of these children and develop existing laws to meet the specific needs of vulnerable children. It is the responsibility and rights of parents and educators to offer guidance in the implementation of rights of these children. They must develop an approach that, takes into account the child’s evolving capacities, such as age and self-realization. Self-identity can be explained as the descriptive characteristics, abilities, qualities, of a person. (Freeman, 2000) Listening to children talk about their right and rights of other, there is need to put in place more active ways of particularly identifying children’s views, mainly when it comes to conducting a research and educational practices. Children, and in particular young ones, should be allowed to express their views in any way possible even through children’s activities like drawing and orally. The meanings young ones attach to their experiences are rarely the meanings that the adults in charge of them would ascribe. (Bandman, 1999) The session will focus on the importance of understanding how children construct and develop their own sense of what their rights are and in what way they develop a sense of belonging within the community and family they come from. It will scrutinize the importance of early experiences in relation to their self-worth. The connection among the vision, belonging, and the shaping of children’s identity will be discussed, including the areas of attachment, social- cultural heritage, developing experiences and progressive relationship structure will be explored. Johnny is a seven-year-old boy in a kindergarten school, he is from a humble background, as the first-born child of four boys, and one girl he is curious about his surroundings. At this age, he can ask questions and seek answers about

How to be an effective communicator Essay Example for Free

How to be an effective communicator Essay Good communicators are not born they are created, and you cannot create one out of yourself overnight. You have to have constant practice and some rules to follow. Other than learning how to speak clearly and avoiding monotonous voice which will definitely play a big part to becoming the best in your chosen career, avoiding plagiarism is also an important thing to consider. What is plagiarism?   Ã¢â‚¬Å"Is using ideas and/or words from a different person, claiming as ones own without proper credit to the real source (Merriam-Webster Dictionary)†.   Ã¢â‚¬Å"The inability to give credit and acknowledge ideas or phrases used in any paper, publication, or project submitted but gained from another person (http://english.la.psu.edu)†. What are the different types of plagiarism? 1.  Ã‚  Ã‚  Ã‚  Ã‚   Word-for-word Plagiarizing – â€Å"happen when you try to change opening part of the sentence, so that the readers won’t notice that the remaining of the entire paragraph is just a copy from the source (http://academics.hamilton.edu)†. 2. Plagiarizing by paraphrase – â€Å"the same concept from the source are being followed in a close manner simply by just substituting and changing some words with your own words and sentenced for those of the original text (http://academics.hamilton.edu)†. 3. The Source – The writer should have proper citation about the source, it should be clear and exact. 4. Mosaic Plagiarism – â€Å"this is more complicated type of plagiarism, because phrases and words are actually from the source or original text and you just add some of your words (http://academics.hamilton.edu)†. 5. Summary – â€Å"using quotation marks during an oral presentation and while writing a paper can help avoid plagiarism, but when overdone it will look like a patchwork and will resemble the original (Types of Plagiarism, http://la.psu.edu).   If it happened that almost the entire thing that you want to say came from one source, directly quote or paraphrase it so it will look better. But either way, introduce your borrowed words or ideas by pointing out that those ideas are from the author and followed them with citation inside the parenthesis (Types of Plagiarism, http://la.psu.edu)†. How do we avoid them in oral presentation? Consider indicating direct quotation, by saying â€Å"quote† and follow it with â€Å"unquote† or â€Å"close quote†. Another approach is by saying: â€Å"In her 1998 owner’s guide, Airedale Terriers, trainer Dorothy Miner says the following about the origins of the Airedale Terrier†. If you are citing a saying from anonymous sources, you can say â€Å"It is always said that†¦Ã¢â‚¬  In oral presentation usually the citation is trimmed down to just the author, Title of the publication date and title. With all these information regarding plagiarism and proper citation I’ am sure it will be a big help for you to start so to speak. But with constant practice and proper usage of voice, using proper intonation, correct stress on words, pronunciation and enunciation you can become one of the most effective communicator.